Question

a single slit of width d is illuminated by violet light of wavelength 400nm and the width of the diffraction pattern is measured as y. When half of the slit width is covered an other half is illuminated by yellow light of wavelength 600nm, then how much the width of diffraction pattern becomes?​

Answer 1

A single slit of width a is illuminated by violet light of wavelength 400nm and the width of the diffraction pattern is measured as y. When half of the slit width is covered and illuminated by yellow light of wavelength 600nm, the width of the diffraction pattern is. ⇒y′y=λ′d′×dλ=600d/2×d400⇒y′=3y.

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Answer 2

Answer:

A single slit of width a is illuminated by violet light of wavelength 400nm and the width of the diffraction pattern is measured as y. When half of the slit width is covered and illuminated by yellow light of wavelength 600nm, the width of the diffraction pattern is. ⇒y′y=λ′d′×dλ=600d/2×d400⇒y′=3y.