Question

A sinker is found to weigh 56.7 gf in water. when the sinker is tied to a cork of weight 6 gf, the combination is found to weigh 40.5 gf in water. Calculate the R. D.of cork

Answer 1

Answer:

0.27

Explanation:

Weight of cork in air = 6 gf

Weight of sinker in water = 56.7 gf

Weight of sinker and cork in water = 40.5 gf

Weight of cork in air and sinker in water = 56.7 + 6 = 62.7 gf

Loss of weight of cork in water = 62.7 - 40.5 = 22.2 gf

RD of cork = weight of cork in air ÷ loss of weight of cork in water

RD = 6 ÷ 22.2 = 0.27