Question

A sinusoidal current has a magnitude of 3 A at 120°. Its maximum value will be​

Answer 1

Answer:

The maximum value of the current is 5.17 A.

Explanation:

Sinusoidal time-varying current is represented in the form of

I = I' Sinωt

where,

I  is the instantaneous current,

I'  is the peak or maximum current

ω is the angular frequency

t is the time.

Now, it is given that a sinusoidal current has a magnitude of 3 A at 120°.

So, I = 3A and sinωt = sin 120° = 0.58

Now, we have,

I = I' Sinωt

I' = I/Sinωt

We enter the values, and we get

The maximum value (I') = 3/0.58 = 5.17 A

Therefore, the maximum value of the current is 5.17 A.

To read more, visit

https://brainly.in/question/30311148

https://brainly.in/question/42670491

#SPJ3

Answer 2

The sinusoidal current in question peaks at 3 A multiplied by 1.41 to get 5.71 A.

The maximum value of a sinusoidal current is the same as its peak value. The peak value of a sinusoidal current can be calculated using its rms (root-mean-square) value or its magnitude.

The RMS value of a sinusoidal current is defined as the square root of the mean of the squares of the current values over a complete cycle. The RMS value of a sinusoidal current is related to its magnitude by the equation: I_rms = I_magnitude / √2.

The magnitude of a sinusoidal current, given as 3 A in the question, can be used to calculate its peak value. The peak value of a sinusoidal current is equal to its magnitude multiplied by √2. Therefore, the peak value of the sinusoidal current in question is 3 A × 1.41 = 5.71 A.

It's important to note that the phase angle of 120° in the question refers to the phase difference between the sinusoidal current and voltage waveforms in an AC circuit. It doesn't have any direct relationship with the peak value of the current.

For more such questions on the sinusoidal current: https://brainly.in/question/54856967

#SPJ3