Question

A sinusoidal voltage of peak value 283 V and frequency 50 Hz is applied to a series LCR circuit in
which R = 32, L = 25.48 mH and C = 796 uF, then the power dissipated at the resonant condition will be:
(A) 39.70 kW
(C) 13.35 kW
(B) 26.70 kW
(D) Zero​

Answer 1

Answer:

26.70

Explanation:

Given questions is wrong the given value of r should be 3

now,in resonance power factor is 1

and z= R

therefore formula for power dissipation is V²/R=

=283×283/3= 26697