A siren emitting sound of frequency 500 Hz is going away form a static listener with a speed of 50m/sec.The frequency of sound to be heared directly from the ziren is ???
Answers
Answered by
6
the formula used in this answer should be.
f*v/v+u . where v is velocity of sound 330m/s
u is speed of siren and f is frequency
therefor.
(500×330)÷330+50=434.21
f*v/v+u . where v is velocity of sound 330m/s
u is speed of siren and f is frequency
therefor.
(500×330)÷330+50=434.21
Answered by
0
Dear Student,
◆ Answer -
Frequency = 434.2 Hz
● Explanation -
# Given -
f = 500 Hz
v = 50 m/s
vs = 330 m/s
# Solution -
Frequency of sound to be heard directly from the siren is -
f' = f × v/(v+vs)
f' = 500 × 330/(330+50)
f' = 500 × 330 / 380
f' = 434.2 Hz
Hence, frequency of sound to be heard directly from the siren is 434.2 Hz.
Thanks dear. Hope this is helpful to you..
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