Question

A six digit number is said to be lucky if the sum of its first three digits is equal to the sum of its last 3 digits. Then the sum of ALL SIX DIGITS [ i.e. THE SUM OF ALL THE SIX DIGIT LUCKY NUMBER ] lucky number is divisible by
(a.) 2
(b.) 5
(c.) 7
(d.) 13
Please give well explained appropriate answers.
It's a question of PRMO so don't take it easily.
ACCORDING TO THE ANSWER KEY, THE ANSWER IS OPTION (d.) i.e. 13.
Many of you are saying that option (a.) is correct but I am not asking for 1 lucky no. The question says to sum all the 6-digit lucky no. not 1 lucky no.

SO PEASE READ THE QUESTION CAREFULLY
So please explain how come!​

Answer 1

If you take an odd number as last digit, then it won't be divisible by 2 but this condition may be satisfied. It may be also won't be divisible by 13. Because, based on your conditions, an example for this lucky number is 123321. But this number is not divisible by 13. So, another number may be the option.For every single number which comes as example satisfying all your conditions will not be divisible by 13. That is for sure. But some numbers may be divisible by 13 and also satisfy your conditions. For example, numbers like 111,111 ; 222,222 ; 333,333 ; 444,444 ; etc.... satisfy your conditions and are also divisible by 13. For more clarification, once ask any one if your teachers about this question and also show my answer.