Question

A six face dice is marked with the numbers 1, 2, 3, 4, 5 and 6. What is the probability of getting a number which is not even?​

Answer 1

Answer:

3/4 ng full k by y in vf unconsciously

Answer 2

Answer:

1/2

Step-by-step explanation:

Given :-

Asix face dice is marked with the numbers 1, 2, 3, 4, 5 and 6.

To find:-

What is the probability of getting a number which is not even?

Solution:-

Given that :

Asix face dice is marked with the numbers 1, 2, 3, 4, 5 and 6.

Total number of all possible outcomes = 6

1,3,5 are the odd numbers among 1,2,3,4,5,6.

The number of favourable outcomes to the odd number =3

=> The number of favourable outcomes to the number which is not even = 3

We know that

Probability of an event E is P(E) = Number of favourable outcomes/Total number of all possible outcomes.

If the die is thrown once,the number getting which is not even is O then

Probability of getting a number which is not even

=P(O)

=3/6

=1/2

Answer:-

The Probability of getting a number which is not even = 1/2

Used formulae:-

Probability of an event E is P(E) = Number of favourable outcomes/Total number of all possible outcomes.