A six-faced dice is tossed. If a prime number occurs, Anil wins that
number of rupees but if a nonprime number occurs, he loses that number
of rupees. Determine whether the game is favourable to the player.
Answers
Step-by-step explanation:
Prime numbers between 1 to 6 => 1,2,3 and 5
Probability => 4/6 = 2/3
Non prime numbers between 1 to 6 => 4 and 6
Probability => 2/6 = 1/3
Thus, Game is favourable to the player.
Given: When a dice is tossed, if a prime number occurs then Anil wins. But if a non-prime number occurs, he loses.
To find: Whether the game is favourable to the player
Solution: In a six-faced dice, the six numbers are 1, 2, 3, 4, 5 and 6.
Out of these six numbers, 2, 3 and 5 are prime numbers.
Now we need to find the probaility of winning.
Probability is given by the formula = number of favourable outcomes/total set of outcomes.
Since when a prime number occurs, Anil wins that number of rupees, the probability of winning = 3/6 = 1/2.
The non-prime numbers are 4 and 6.
Now if a non-prime number occurs, he loses that number of rupees, the probability of losing = 2/6 = 1/3.
As we can see probability of winning is more than the probability of losing
(1/2 > 1/3), the game is favourable to the player.
Answer: The game is favourable to the player.