A six faced unbiased die is thrown twice and the sum of the numbers appearing on the upper face is observed to be 7.The probability that the number 3 has appeared at least once is
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Answered by
3
Answer:
Given that sum of numbers appeared on upper surface is 7. So, Set of numbers that have appeared on the upper surface are (1,6),(6,1),(2,5),(5,2),(3,4),(4,3).
Out of these only two have at least one 3
So, Probability =
6/2= 3/1
Answered by
5
Answer:
I think 1/3
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