Math, asked by xxsergioxx333, 3 months ago

A six-sided cube with the letters S, O, L, V, E, D is rolled twice. What is the probability of rolling two consonants? Express as a fraction in simplest form.

Answers

Answered by vkvyas80
3

Probability is equal to desired outcome divided by total number of outcomes. Desired outcomes for the two rolls to sum to 8 are (2,6) (3,5) (4,4) (5,3) (6,2). This is 5 desired outcomes. There are 6 numbers on cube 1,2,3,4,5,6, so Total possible outcomes (denominator) are 6*6 = 36. So using the definition above. The answer is C. 5 desired outcomes divided by 36 total possible outcomes.

Answered by xxbadgirlxx63
3

Total possibilities on the first roll = 6

Total possibilities on the second roll = 6

Total possible outcomes = 6*6 = 36 ways

Sum of the two rolls can be 8 in the following ways: {2, 6}, {3, 5}, {4, 4}, {5, 3}, {6, 2} = 5 ways

Probability = 5/36

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