Question

A skateboarder is moving in a straight line at a speed of 3 m/s and comes to a stop in 2 seconds. Calculate the deceleration

Answer 1

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Answer 2

Answer:

-1.5 m/s^2 is the deceleration

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Explanation:

formula of acceleration is

$a = \frac{v - u}{t}$

where v = final velocity

u = initial velocity

t = time interval

deceleration = negetive of acceleration

therefore,

v = 0 m/s

u = 3 m/s

t = 2 sec

$d = \frac{0 - 3}{2}$

$d = \frac{ - 3}{2} = -1.5$