Social Sciences, asked by yashkushwaha32, 8 hours ago

a skateboarder is traveling at 8m/s. he slows and come to a stop in 4 sec. what was the acceleration?​

Answers

Answered by ayoubalfia3
0

Acceleration = v-u

t

= 8m/s - 0m/s

4 sec

= 2m/s^2

hope it is correct and may help you ☺️

Answered by rastogiarnav86
0

Answer:

The answer is -2m/s^{2}

Explanation:

As we know that accleration = ΔV/ ΔT or v-u/t (final velocity - initial velocity/time).

Here, initial velocity = 8m/s^{2}  and final velocity = 0m/s^{2}.

So, by applying the above equation we get:

0 - 8/ 4 = -8/4 = -2m/s^{2}.

Therefore, the acceleration will be -2m/s^{2} but the retardation will be 2m/s^{2}.

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