Question

a skateboarder is traveling at 8m/s. he slows and come to a stop in 4 sec. what was the acceleration?​

Answer 1

Acceleration = v-u

t

= 8m/s - 0m/s

4 sec

= 2m/s^2

hope it is correct and may help you ☺️

Answer 2

Answer:

The answer is -2m/$s^{2}$

Explanation:

As we know that accleration = ΔV/ ΔT or v-u/t (final velocity - initial velocity/time).

Here, initial velocity = 8m/$s^{2}$  and final velocity = 0m/$s^{2}$.

So, by applying the above equation we get:

0 - 8/ 4 = -8/4 = -2m/$s^{2}$.

Therefore, the acceleration will be -2m/$s^{2}$ but the retardation will be 2m/$s^{2}$.