Question

A skateboarder traveling at 7.0 meters per second rolls to a stop at the top of a ramp in 3.0 seconds. What is the skateboarder’s acceleration?

Answer 1

Answer:

2.33 m/s² (retardation)

Explanation:

final velocity (v) = 0

initial velocity (u) = 7 m/s

time taken (t) = 3s

v = u + at

0 = 7 + a(3)

3a = -7

a = -2.33

minus sign shows retardation

hope it helps...

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Answer 2

The skateboarder's acceleration is -2.33 m/s²

Kinematics equations:

Kinematics equations are a set of mathematical equations that describe the motion of objects.

These equations relate the variables of motion, including displacement, velocity, acceleration, time, and position.

From basic kinematic equations: v = u + at

Use the above equation to find the acceleration

Rearranging the equation, we get:

a = (v - u) / t

Calculation:

From the question

The final velocity v = 0 [ since the skateboarder comes to a stop]

The initial velocity u = 7.0 m/s  

Time taken by the skateboarder to reach the top t = 3.0 seconds

Substituting the values we have:

a = (0 - 7.0) / 3.0

a = -2.33 m/s²

Therefore,

The skateboarder's acceleration is -2.33 m/s²

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