A skier, starting from rest, accelerates down a slope at 1.6 m/s^2.How far has he gone at the end of 5second
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Given conditions ⇒
Acceleration(a) = 1.6 m/s².
Initial Velocity(u) = 0
Final Velocity = v
Time = 5 seconds.
Using the Formula,
Acceleration = (v - u)/t
1.6 = (v - 0)/5
v = 1.6 × 5
v = 8 m/s.
Hence, the Final Velocity of the Skier is 8 m/s.
Hope it helps.
Acceleration(a) = 1.6 m/s².
Initial Velocity(u) = 0
Final Velocity = v
Time = 5 seconds.
Using the Formula,
Acceleration = (v - u)/t
1.6 = (v - 0)/5
v = 1.6 × 5
v = 8 m/s.
Hence, the Final Velocity of the Skier is 8 m/s.
Hope it helps.
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Tnxx....... it will help you guy
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