a skier starting from rest accelerates down a slope at 1.6 m/s^2. how much time is required for the skier to reach a speed of 7.8 m/s
kvvijin77:
what is the angle made by the slope with horizontal?
Answers
Answered by
0
Hey dear here is the answer
Answer:
Acceleration:
1.6
m
s
2
Distance:
20
.
m
Explanation:
We can use the equation
v
x
=
v
0
x
+
a
x
t
To find the acceleration, assuming it's constant, of this motion. The initial velocity
v
0
x
is
0
, as it started from rest. Thus, the acceleration is
a
x
=
v
x
t
=
8.0
m
s
5
s
=
1.6
m
s
2
Now, to find the distance
Δ
x
the skier travels, we'll use the equation
Δ
x
=
v
0
x
t
+
1
2
a
x
t
2
Plugging in known variables, the distance
Δ
x
the skier traveled is
Δ
x
=
(
0
)
(
5.0
s
)
+
1
2
(
1.6
m
s
2
)
(
5.0
s
)
2
=
20
.
m
Read more on Brainly.in - https://brainly.in/question/3885523#readmore
Hope it's help you
Answer:
Acceleration:
1.6
m
s
2
Distance:
20
.
m
Explanation:
We can use the equation
v
x
=
v
0
x
+
a
x
t
To find the acceleration, assuming it's constant, of this motion. The initial velocity
v
0
x
is
0
, as it started from rest. Thus, the acceleration is
a
x
=
v
x
t
=
8.0
m
s
5
s
=
1.6
m
s
2
Now, to find the distance
Δ
x
the skier travels, we'll use the equation
Δ
x
=
v
0
x
t
+
1
2
a
x
t
2
Plugging in known variables, the distance
Δ
x
the skier traveled is
Δ
x
=
(
0
)
(
5.0
s
)
+
1
2
(
1.6
m
s
2
)
(
5.0
s
)
2
=
20
.
m
Read more on Brainly.in - https://brainly.in/question/3885523#readmore
Hope it's help you
Answered by
0
In the acceleration = 1.6m/s^2
starting velocity = 0
final velocity = 7.8m/s
find time.
V= u+at
7.8= 0+1.6t
t= 7.8/1.6= 78/16= 4.875 s
starting velocity = 0
final velocity = 7.8m/s
find time.
V= u+at
7.8= 0+1.6t
t= 7.8/1.6= 78/16= 4.875 s
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