A skier, starting from rest, accelerates down a slope at 1.6m/s² .How far has he gone at the end of 5 s.
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Answered by
1
Answer:
8 m/s.
Explanation:
Given conditions ⇒
Acceleration(a) = 1.6 m/s².
Initial Velocity(u) = 0
Final Velocity = v
Time = 5 seconds.
Using the Formula,
Acceleration = (v - u)/t
1.6 = (v - 0)/5
v = 1.6 × 5
v = 8 m/s.
Hence, the Final Velocity of the Skier is 8 m/s.
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0
Answer:
THE ANSWER IS 8m/s^2
Explanation:
AS WE KNOW THE FORMULA OF SPEED IS DISTANCE /TIME,THE FORMULA OF DISTANCE COVERED IS SPEED*TIME.HERE THE QUESTION STES TO FIND THE DISTANCE COVERD.WHENN THE FORMULA OF SPEED IS DISTANCE/TIME THE FORMULA OF DISTANCE COVERED IS SPEED * TIME .THUS 1.6/s^2 * 5s GIVES US THE ANSWER 8m/s^2.
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