A skydiver was released (with zero initial velocity) from a helicopter at a certain distance from the surface of the ground. Unfortunately, her parachute did not open and she hit the ground with the velocity of 180 km/h. Acceleration during her journey was approximately 10 m/s2. Then the time taken by her to reach the surface of the Earth is
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Explanation:
By 1 eq. of motion.
v=u+at
change km/hr into m/sec
180km/hr= 50m/sec
50=0+10×t
50=10t
t=50÷10=5sec
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