Physics, asked by satya5135, 10 months ago

A skylab of mass m kg is first launched from the surface of thr earth. The additional velocity now imparted to the spaceship in the orbit to overcome the gravitational pull is

Answers

Answered by monica789412

0

V=√GM/2R

Explanation:

The speed required to place the Skylab aircraft in an orbit of radius 2R is v,then

GMm/(2R)²=mv²/2R

∴ V=√GM/2R

its K.E =1/2 mv²=1/2GMm/2R=2GMm/4R

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