Physics, asked by einstien276, 1 year ago

A slab of material of dielectric constant k has the area (1/4)th as that of the plates of a parallel plate capacitor and has thickness 3 4 d where d is the separation of plates. how is the capacitance changed when the slab is inserted between the plates?

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Answered by khushdeep1546
1

Answer:

A slab of material of dielectric constant K has the same area as that of the plates of a parallel plate capacitor but has the thickness 2d/3, where d is the separation between the plates. Find out the expression for its capacitance when the slab is inserted between the plates of the capacitor.Read more on Sarthaks.com - https://www.sarthaks.com/59623/slab-material-dielectric-constant-has-the-same-area-that-plates-parallel-plate-capacitor

Explanation:

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