Question

A slab vonsists of two parallel layers of two different materials of same thickness and having thermal conductivities k1 and k2. The equivalent thermal conductivity is

Answer 1

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Let two slabs of same thickness t and area of cross section A be joined.

Resultant conductance is given by-

k = (k1A + k2A) / (A + A)

k = (k1 + k2) / 2

Thermal conductivity of the combination is (k1+k2)/2 .

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Answer 2

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