Question

A slit is placed at one end of an optical bench and illuminated by green light of wavelength 5000 A. A vertical straightedge is mounted parallel to the slit and 50.0 cm away. Observations of the diffraction pattern produced by the straightedge are made 50.0 cm beyond. What would be the intensity (a) 0.40 mm inside the edge of the geometrical shadow of the straightedge at the observation plane and (b) 0.40 mm outside the edge?​

Answer 1

Answer:

Monochromatic light of wavelength 580 nm passes through a single slit and the diffraction pattern is observed on a screen. Both the source and screen are far enough from the slit for Fraunhofer diffraction to apply. (a) If the first diffraction minima are at 90.0, so the central maximum completely fills the screen, what is the width of the slit? (b) For the width of the slit as calculated in part (a), what is the ratio of the intensity at = 45.0 to the intensity at = 0?