Question

A slot machine takes only 10 cent and 50 cent coins and contains
a total of twenty-one coins altogether. If the value of the coins is
$4.90, find the number of coins of each value.​

Answer 1

Answer:

Let the no of 50c coins be x

Then the no of 10c coins will be (21 -x)

VALUE = 0.50x + 0.10(21-x) = 4.90

0.50x + 2.1 - 0.10x = 4.90

0.40x = 2.80

x = 7

ANSWER 7 (50c) coins AND 14 (10c) coins

CHECK

7 X 0.50 = 3.50

14 X0.10 = 1.40

ADD = $4.90

pls mark me as brainlist

Answer 2

Answer:

$\huge\star{\underline{\mathtt{\red{A}\pink{N}\green{S}\blue{W}\purple{E}\orange{R}}}}⋆$

Let the no of 50c coins be x

Then the no of 10c coins will be (21 -x)

VALUE = 0.50x + 0.10(21-x) = 4.90

0.50x + 0.10(21-x) = 4.900.50x + 2.1 - 0.10x = 4.90

0.50x + 0.10(21-x) = 4.900.50x + 2.1 - 0.10x = 4.900.40x = 2.80

0.50x + 0.10(21-x) = 4.900.50x + 2.1 - 0.10x = 4.900.40x = 2.80x = 7

ANSWER 7 (50c) coins AND 14 (10c) coins

CHECK

7 X 0.50 = 3.50

7 X 0.50 = 3.5014 X0.10 = 1.40

7 X 0.50 = 3.5014 X0.10 = 1.40ADD = $4.90

_____________________

@MsElegant