Question

A small air bubble in a glass sphere of radius 2cm appears to be 1cm from the surface when looked at along a diameter.If the refractive index of glass is 1.5,find the true position. Of the air bubble

Answer 1

Answer:

The Position of the air bubble is 0.8 cm from the surface.

Explanation:

Given that,

Refractive index of glass$\mu_{2} =1.5$

Radius of glass sphere R = -2 cm

The distance of the glass = 1 cm

We need find out the position of air bubble

Using the formula

$\dfrac{\mu_{2}}{v}-\dfrac{\mu_{1}}{u}=\dfrac{\mu_{2}-\mu_{1}}{-R}$

We know ,

Refractive index of air $\mu_{1} =1$

Put the value into the formula

$\dfrac{1.5}{-1}-\dfrac{1}{u}=\dfrac{1.5-1}{-2}$

$-\dfrac{1}{u}=\dfrac{0.5}{-2}+\dfrac{1.5}{1}$

$-\dfrac{1}{u}=\dfrac{5}{4}$

$-u=\dfrac{4}{5}$

$u = 0.8\ cm$

Hence, The Position of the air bubble is 0.8 cm from the surface.