Question

a small ball hits obliquely a smooth and horizontal surface with speed u whose x component is.2m/s and y component4m/s.if the coefficirnt of restitutuon is 1/2then x and y componemts just after collision of the velocity will be？

Answer 1

Explanation:

vx does not change... vy changes along y axis

Answer 2

Answer:

Horizontal component is 2 m/s

Vertical component is 2 m/s

Explanation:

The x component of the speed

$u_x=2$ m/s

The y component of the speed

$u_y=4$ m/s

Given, the coefficient of restitution

$e=\frac{1}{2}$

When the ball will hit the surface, it will turn back

Since the effect due to the coefficient of restitution will be only in the direction perpendicular to the surface, i.e. in vertical direction

Therefore, only the vertical component of the speed will change

Thus,

Horizontal speed after impact

$v_x=2$ m/s

Vertical speed after impact

$v_y=e\times u_y$

$\implies v_y=\frac{1}{2}\times 4$

$\implies v_y=2$ m/s

Hope this helps.