Physics, asked by beingshivani7, 1 year ago

A small ball is projected in x-y plane as shown in the figure under the influence of gravity. The equation of trajectory of the particle is y = 9x - 12x^{2} (where y and x are in metres). The time of flight of the particle is

Answers

Answered by tummalaxmisai007
8

Answer:

According to the trajectory

y=Ax-Bx^2

R=A/B

Hmax=A^2/4B

H =1/2*gt^2

y=9x-12x^2

Hmax=81/4*12=27/20

T=under root 2h/g=under root 27/10

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