A small ball moving with velocity 10m/shorizontally strikes a rough surface .coefficient of restitution =0.4.Horizontal component of ball after 1st impact will be?
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which is 10m/s
after bounce it will be 4 m/s just after leaving ground
becoz of gravity it will slow down and fall afain
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Ans is given 3m/s .
sorry but for the given question it is correct
if we consider friction we need mass of object which is not given
i am sure about 4 mps
Ty sir
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Answer:
time taken to reach the ground is √(2h/g). so here time taken is 1s as it is falling from a height of 5m.
now vertical speed is -gt i.e. 10m/s
therefore, when the ball lands, its horizontal speed and vertica speed both are 10.
coefficient of restitution changes only vertical component from 10 to 4m/s. and horizontal component is changed by friction
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