Question

A small ball of mass 200g is thrown horizontally with a constant speed of 10 m/s. The ball hits the wall and reflected with the same speed. What is the change in linear momentum of the ball?

Answer 1

Dear Student,

◆ Answer -

∆P = 4 kgm/s

● Explanation -

# Given -

m = 200 g = 0.2 kg

v = 10 m/s

# Solution -

When the mass is approaching the wall, linear momentum is -

Pi = mv

Pi = 0.2 × 10

Pi = 2 kgm/s

When the mass is moving away from the wall, linear momentum is -

Pf = -mv

Pf = -0.2 × 10

Pf = -2 kgm/s

Change in the momentum is calculated as -

∆P = Pi - Pf

∆P = 2 - (-2)

∆P = 4 kgm/s

Therefore, change in linear momentum of the ball is 4 kgm/s.

Hope this helps you...