Question

A small ball of weight 10 N is suspended by two cords A and B as shown in the
figure. Values of tensions in the strings A and B are
37°
53

Answer 1

100N=F

Cord A and B

The tension in the horizontal cord A

We know that there is a gravitational force on the circular weight of 100N directed down. Since the string to the left of the weight can only affect the left and right components of the equilibrium,

We know the vertical component of the tension in the cord must ne equal to the gravitational force of the weight.

Thus we need to have that 100=T [Slanted cord] sin(30

o

)

Thus this implies that the tension in the slanted cord

100=T

slanted

×sin30

o

or, T

slanted

=

sin30

o

100

=

1/2

100

=200N .