a small bar magnet has a magnetic moment 1.2 a square the magnetic field at a distance 0.1 m on its axial lines will be dash into 10 power of minus 4 and you not is equals to 45 into 10 power of minus 7 by M
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Answer:
As the neutral points are on the axial line, so using
4π
μ
o
(r
2
−l
2
)
2
2Mr
=B
H
Given: 2l=20cm=0.2m ;B
H
=3.2×10
−5
T; r=0.4m
10
−7
×
(0.4
2
−0.1
2
)
2
2M(0.4)
=3.2×10
−5
⟹M=9
Now, m(2l)=M
Thus, m(0.2)=9⟹m=45
Hence, pole strength of magnet is 45Am
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