A small bead of mass m is given an initial velocity of magnitude v on a horizontal circular wire. If the coefficient of kinetic friction is μk, then determine the distance travelled before it comes to rest. Given that radius of circularwire is r
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We assume that gravitation is perpendicular to the plane of motion (system horizontal). Now applying work energy theorem
Kfinal-kinitial=-ukmg.s
Kfinal=0
Kinitial=1/2mv^2
We equate and get
s=v^2/ukg
Kfinal-kinitial=-ukmg.s
Kfinal=0
Kinitial=1/2mv^2
We equate and get
s=v^2/ukg
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