A small block B is placed on another block A of mass 5 kg and length 20 cm. Initially, the block B is near the right end of block A (Figure 5−E3). A constant horizontal force of 10 N is applied to the block A. All the surfaces are assumed frictionless. Find the time that elapses before block B separates from A.
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33
Answer:
The time that elapses before block B separates from A is 0.44s
Explanation:
Mass of block A, m = 5 kg
F = ma = 10 N
⇒a=10/5=2 m/s²
As there is no friction between A and B, when block A moves, block B remains at rest in its position.
Initial velocity of A u = 0 m/s
Distance covered by A to separate out,
s = 0.2 m
Using
s=ut+1/2at², we get:
0.2=0+1/2×2t²
⇒ t² = 0.2
⇒ t = 0.44 s
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