A small block of m 1 kg is attached to k=100 find velocity when extensuon is 0.1m
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Answer:
force by the spring=0.1×100
=10
m=1kg
F=ma
a=10m/s^2
s=0.1
v^2=2as
v^2=2×10×0.1
v=√2
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answer is 1m/s........
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