Question

A small block of mass 0.2 kg is released
from rest from a height of 5.0 m. The block
follows a curved path to the ground and
falls on a spring at the base of the path. If
the spring constant is 600 Nm, calculate
the maximum compression of the spring
Take g = 10 ms?
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Answer 1

Answer:

kiya question hai bhai ek number

Answer 2

Answer:

x=(-0.179) or x= (0.186)

Step-by-step explanation:

initial P.E= mg(h+x)

final P.E= 0.5*kx^2

initial P.E= final P.E

mg(h+x)=0.5*kx^2

600x^2-4x-20=0

x=(-0.179)

x=(0.186)