A small block of mass m is kept on a rough inclined surface of inclination θ fixed in an elevator.
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Answered by
64
Distance travelled by the elevator in 't' time is = vt
As the block does not slide on the wedge. So friction force, f= mg sinθ
Angle between d and f is (90 - θ)
Work done by the force friction on the block in time t will be = F.d
That is,
Work, W
= Fd cos (90 - θ)
= mg sin θ . vtsin θ
= mg vtsin^2θ
Thus, the work done by the force of friction in time t will be mgvtsin^2θ
As the block does not slide on the wedge. So friction force, f= mg sinθ
Angle between d and f is (90 - θ)
Work done by the force friction on the block in time t will be = F.d
That is,
Work, W
= Fd cos (90 - θ)
= mg sin θ . vtsin θ
= mg vtsin^2θ
Thus, the work done by the force of friction in time t will be mgvtsin^2θ
Answered by
8
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