Question

A small block of wood of mass 9 kg is floating on water. Find the force of buoyancy acting on the block. (g = 10 ms2)

Answer 1

Explanation:

When a body floats on the surface of water. It experiences a force that keeps it floated and acts in the upward direction.

This force is equal to the weight of the body but acts in the opposite direction to that of weight.

Since we know, weight of the body is given by

F= w= ma

W = 9 * 10 = 90 N

Hence, the force of buoyancy is 90 N in upward direction