Question

A small body of mass m is placed i the top of a hemispherical

Answer 1

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Answer 2

HEY MATE!.....




F = mgsinθ - N

When the ball loses contact, the normal force (N) = 0

=> F = mgsinθ

Since the ball is moving in a circular path, F = mv² / R

mgsinθ = mv² / R

=> v² = Rgsinθ


From conservation of energy, you know that:

mgR = ½mv² + mgh

Rg = ½Rgsinθ + gh

h = R - ½Rsinθ

If you draw out a force diagram you'll see that sinθ = h / R

h = R - ½Rh / R

3h/2 = R

h = 2R/3

So it will lose contact (2/3)rd of the way up.


it may be helps u