Math, asked by xxaestheticjk, 18 days ago

A small candle 2.5 cm in size is placed in front of the concave mirror of radius of curvature 36 cm. if the candle is moved close to the mirror, how will the screen has to be moved​

Answers

Answered by PopularStar
24

S O L U T I O N:-

Object distance, u=−27cm

Radius of curvature of the concave mirror, R=−36cm

focal length of mirror f= \sf \dfrac{R}{2} =−18cm

The image distance can be obtained using the mirror formula,

v1+u1=f1

From above equation, v=−54cm.

Therefore, the screen should be placed 54 cm away from the mirror to obtain a sharp image. The magnification of the image is given as,

m=hh′=−uv

∴h′=−5cm

The height of the candle’s image is 5 cm. The negative sign indicates that the image is inverted and virtual. If the candle is moved closer to the mirror, then the screen will have to be moved away from the mirror in order to obtain the image.

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