A small college has 800800800 students, 10\%10%10, percent of which are left-handed. Suppose they take an
SRS
of 888 students. Let L=L=L, equals the number of left-handed students in the sample.
Which of the following would find P(L=2)P(L=2)P, l
eft parenthesis, L, equals, 2, right parenthesis?
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Given : A small college has 800 students
10% of which are left-handed.
Sample of 8 students taken
To Find : Probability of 2 left handers in sample
Solution:
left-handed. are 10 %
=> p = 1/10
q = 1 - p = 9/10
sample of 8 has been taken
n = 8
Probability of 2 left handers has to find
x = 2
P(x) = ⁿCₓpˣqⁿ⁻ˣ
P (2) = ⁸C₂(1/10)²(9/10)⁶
= 28 * 9⁶ / 10⁸
= 0.1488
= 14. 88 %
Probability of 2 left handers = 0.1488 or 14. 88 %
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