Question

A small dipole of dipole moment 'p' is kept at the centre of a ring of radius 'a' and uniformly distributed charge 'q'. The dipole moment has direction along the axis of the ring. The resultant force on the ring due to dipole is ?

Answer 1

Answer:

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Electric field at each point on the surface of ring due to the dipole is E=kpR3 in direction opposite to the dipole moments .(figure below)

Hence net force on ring is F=QE=kpQR3

Alternate solution

Electric field due to ring at pointP on its axis at a distance x from the centre O of the ring is

E=k.Qx(x2+R2)3/2,dEdx]atx=0=kQR3

Force on dipole =dEdx=kQpR3

Explanation:

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