Question

a small electric motor is used to lift a 0.50 kilogram mass at a constant speed. If the mass is lifted at a vertical distance of 1.5 meters in 5 seconds, the average power developed by the motor is

Answer 1

Answer:

1.47W

Explanation:

W.k.t formula for potential energy=mgh

Mass;distance;time are given

So it is easy to find power

Power=energy/time

=Mgh/t

When we apply this in formula we get the answer 1.47W/joule per second.

I hope this answer is correct and you can understand

Answer 2

Given:

• Mass = 0.50 Kg
• Distance = 1.5 m
• Time = 5 secs

To Find:

• The average power developed by the motor.

Solution:

The formula to find the power is given by,

Power = energy/time → {equation 1}

We need to find the value of energy in order to find power. The formula is,

Change in potential energy = m×g×h → {equation 2}

Where "m" is the mass, "h" is the height or distance, and "g" is the gravitational force.

On substituting the given values in equation 2 we get,

⇒ Energy = 0.50×9.8×1.5 {multiplying the terms}

⇒ Energy = 7.35 J

Now on substituting the value of "energy" and "time" in equation 1 we get,

⇒ Power = 7.35/5 {dividing the terms}

⇒ Power = 1.47 watts

∴ The average power developed by the motor = 1.47 watts.