Question

A small flat search coil of area 5cm square with 140 closly wound turns is place between the poles of a powerfull magnet producing magnetic field .09t and the quicklyn removed out of the field regin. Calcullate (a) change of magnetic flux through the coil and, and (b) emf induced

Answer 1

Answer:

Vucucvu vivu आईबी iviv b

Answer 2

Answer:

(a). The change of magnetic flux through the coil is $-6.3\times10^{-3}\ Wb$.

(b). The induced emf is $6.3\times10^{-3}\ V$

Explanation:

Given that,

Area of coil = 5 cm²

Number of turns = 140

Magnetic field = 0.09 T

(a). We need to calculate the magnetic flux through the coil

Using formula of magnetic flux

$\phi=NBA\cos\theta$

Put the value into the formula

$\phi=140\times0.09\times 5\times10^{-4}\times\cos0$

$\phi=0.0063\ Wb$

$\phi=6.3\times10^{-3}\ Wb$

Now, the change of magnetic flux through the coil

$\Delta \phi=\phi_{f}-\phi_{i}$

$\Delta \phi=0-6.3\times10^{-3}$

$\Delta \phi=-6.3\times10^{-3}\ Wb$

The change of magnetic flux through the coil is $-6.3\times10^{-3}\ Wb$.

(b). Let the coil is removed in a very short period of time interval

So, dt = 1 sec

We need to calculate the induced emf

Using formula of emf

$\epsilon=\dfrac{d\phi}{dt}$

Put the value into the formula

$\epsilon=\dfrac{6.3\times10^{-3}}{1}$

$\epsilon=6.3\times10^{-3}\ V$

The induced emf is $6.3\times10^{-3}\ V$

Hence, This is the required solution.