A small hole is made at the bottom of a
symmetrical jar as shown in figure. A liquid is
filled into the jar upto a certain height. The rate of
descension of liquid is independent of the level of
liquid in the jar. Then the surface of jar is a
surface of revolution of the curve
Answers
Answered by
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n = 4
Explanation:
Let the height of liquid be denoted by y.
Given that dy/ dx = constant.
According to the equation of continuity, we get:
πx²(-dy/dx) = a√2gy
where a is the area of the hole at the bottom and g is gravity, both are constant.
√K . x² = √y
Squaring on both sides, gives you:
y = K.x^4
The surface of jar is a surface of revolution of the curve y=kx^n.
Comparing both, we find that n = 4.
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