Question

A small hole is made in a hollow sphere whose wall are at 723c find the total energy radiated per second per cm square

Answer 1

Answer:

T=723 + 273 =996k

given value :- 5.7× 10^-5

Total energy radiated per sec per cm

e=sigma ×(t)^4

e=5.7×10^-5 × (996)^4

= 5.61×10^7 erg.....

Answer 2

Three steps solutions

Explanation:

Given,

T = 723 °C

Or,

T = 723 + 273 = 996 K

We know that,

total energy radiated per sec per $cm^2$ ,

E = $\sigma \times T^4$

∵$\sigma = 5.7\times 10^ {-5}$  erg⋅cm−2⋅s−1⋅K−4.

∴ E =$5.7\times 10^{-5} \times (996)^4$

E = $5.6\times 10^{7}$ erg