Question

A small indoor greenhouse (herbarium) is made entirely of glass panes (including
base) held together with tape. It is 30 cm long, 25 cm wide and 25 cm high.
(i) What is the area of the glass?
(ii) How much of tape is needed for all the 12 edges?

Answer 1

${\huge{\boxed{\boxed{\red{answer}}}}}$

Area = (Side 1 × Side 2) × sin (angle) or A = (s1 × s2) × sin(θ)

hope it helps mark as brainliest answer

Answer 2

Solution :-

The herbarium is looks like a cuboid.

Here,

• length (l) = 30 cm,
• breadth (b) = 25 cm
• height (h) = 25 cm

(i) Surface area of the herbarium (glass)

= 2[lb + bh + hl]

= 2[(30 x 25) + (25 x 25) + (25 x 30)]${cm}^{2}$ – 2[750 +625 +750]${cm}^{2}$

= 2[2125]${cm}^{2}$

= 4250 ${cm}^{2}$

Thus, the required area of the glass

⠀⠀⠀ = 4250${cm}^{2}$

____________

(ii) Total length of 12 edges

⠀⠀⠀⠀ = 4l + 4b + 4h

⠀⠀⠀⠀⠀= 4(l + b + h)

⠀⠀⠀⠀⠀= 4(30 + 25 + 25) cm

⠀⠀⠀⠀⠀= 4 x 80 cm = 320 cm

Thus, the required length of tape

= ${\boxed{\large{\bold{320cm}}}}$