Question

A small indoor greenhouse (herbarium) is made entirely of glass panes (including
base) held together with tape. It is 30 cm long, 25 cm wide and 25 cm high,
6) What is the area of the glass?
6) How much of tape is needed for all the 12 edges?

Answer 1

Answer:

6) Area = 4250 cm²

6) 320 cm of tape is required

Step-by-step explanation:

6) Area of glass needed = TSA of cuboid

                                         = 2(lb + bh + lh)

                                         = 2(30x25 + 25x25 + 30x25)

                                         = 2(750 + 625 + 750)

                                         = 2(2125)

                                        = 4250 cm²//

6) Tape needed for all 12 edges = 4(l + b + h)

                                                      = 4(30 + 25 + 25)

                                                      = 4(80)

                                                      = 320 cm//

Please mark as brainliest

Answer 2

Question ::-

A small indoor greenhouse (herbarium) is made entirely of glass panes (including base) held together with tape. It is 30 cm long, 25 cm wide and 25 cm high.

(i) What is the area of the glass?

(ii) How much of tape is needed for all the 12 edges?

Given ::-

• Length = 30cm

• Breadth = 25cm

• Height = 25cm

• Greenhouse is herbarium.

To find ::-

• Area of glass ?

• How much of tape is needed for all the 12 edges?

Solution ::-

The herbarium is like a cuboid.

Here,

• length (l) = 30 cm,
• breadth (b) = 25 cm,
• height (h) = 25 cm

_________

(i) Surface area of the herbarium (glass)

= 2[lb + bh + hl]

= 2[(30 x 25)+(25 x 25)+(25 x 30)]${cm}^{2}$– 2[750+625+750] ${cm}^{2}$

= 2[2125] ${cm}^{2}$

= 4250 ${cm}^{2}$

Thus, the required area of the glass

= 4250 ${cm}^{2}$

_________

(ii) Total length of 12 edges = 4l + 4b + 4h

= 4(l + b + h)

= 4(30 + 25 + 25) cm

= 4 x 80 cm = 320 cm

Thus, the required length of tape = 320 cm

___________