Question

A small indoor greenhouse(herbarium) is made entirely of glass panes(including base) held together with tape. It is 30cm long,25cm wide and 25cm high.
(i).How much of tape is needed for all the 12 edges?
[Calculate the sum of all the edges (The 12 edges consist of 4 lenghts, 4 breadths and 4 heights)]
pls answer this question ❤️​

Answer 1

Answer:

$(i)4250 \: {cm}^{2}$

$(ii)320cm$

Step-by-step explanation:

$\large{\pink{(i)\;Area\;of\;glass}}$

Given :

length , l = 30 cm

breadth , b = 25 cm

height , h= 25 cm

To Find :

Area of glass

Solution :

$\bf{\red{T.S.A = 2(lb+bh+hl)}}$

➪ T.S.A = 2 ( 30×25 + 25×25 + 25 × 30)

➪ T.S.A = 2 (750 + 625 + 750)

➪ T.S.A = 2(2125)cm^2

$\pink \implies \: 4250 {cm}^{2}$

___________________________

$\bf{\red{Tape\;needed\;for\;all\;12\;edges}}$

length , l = 30 cm

breadth,b = 25 cm

height ,h = 25 cm

length of tape for all 12 edges =

4 ( l + b + h )

➪ 4 ( 30 + 25 + 25 ) cm

➪ 4 ( 80 ) cm

$\orange \implies320 \: cm$