Question

A small indoor greenhouse (herbarium) is made entirely of glass panes (including base) held together with tape. It is 30cm long, 25 cm wide and 25 cm high.

(i)What is the area of the glass?

(ii)How much of tape is needed for all the 12 edges?
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Answer 1

Answer:

Given:

⇒l=30,b=25,h=25

(i) Total S.A of green house

=2(lb+bh+lb)

=2(30×25+30×25+25×25)

=4250 cm

2

(ii) For 12 edges: Total length

=4l+4b+4h

=4(30+25+25)

=320 cm

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Answer 2

[Image refers to the attachment.]

Given:-

• l = 30 cm
• b = 25 cm
• h = 25 cm

$\sf \: ➊ \: Total \: surface \: area \: of \: greenhouse$

$\sf \: Area \: of \: the \: glass = 2[lb+lh+bh]$

$\sf \longrightarrow \: [2(30×25+30×25+25×25)]$

$\sf \longrightarrow \: [2(750+750+625)]$

$\sf \longrightarrow \: (2×2125)$

$\sf \longrightarrow \: 4250 \: {cm}^{2}$

ㅤ

Total surface area of the glass is 4250 cm².

ㅤ

$\sf \: ➋ Area \: of \: 12 \: glass = 4(l+b+h)$

$\sf \longrightarrow \: [4(30+25+25)]$

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ(after substituting the values)

$\sf \longrightarrow 320 \: {cm}^{2}$

ㅤㅤ

Therefore, 320 cm tape is required for all the 12 edges.