a small indoor greenhouse is made entirely of Glass panes held together with tape it is 30 cm long 25 cm wide and 25 cm high what is the area of the glass and how much of tape is needed for all the 12 edge
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Question :-
A small indoor greenhouse (herbarium) is made entirely of glass panes (including base) held together with tape. It is 30 cm long, 25 cm wide and 25 cm high.
(i) What is the area of the glass?
(ii) How much of tape is needed for all the 12 edges?
Answer :-
The herbarium is like a cuboid.
Here, length (l) = 30 cm,
breadth (b) = 25 cm,
height (h) = 25 cm
(i) Surface area of the herbarium (glass)
= 2[lb + bh + hl]
= 2[(30 x 25) + (25 x 25) + (25 x 30)] cm^2 – 2[750 + 625 + 750] cm^2
= 2[2125] cm^2
= 4250 cm^2
Thus, the required area of the glass = 4250 cm^2
(ii) Total length of 12 edges = 4l + 4b + 4h
= 4(l + b + h)
= 4(30 + 25 + 25) cm
= 4 x 80 cm = 320 cm
Thus, the required length of tape = 320 cm
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