Question

A small light bulb is connected to a 6 V battery and draws 2 A of current. What is the net resistance of the bulb?

Answer 1

Answer:

v=ir therefore R=v/i then R=3

Answer 2

The net resistance of the bulb is equal to 3 ohm

Explanation:

Given,

• The potential difference across the battery is said to be 6 volt.

• Also the current flowing in the circuit is is 2 ampere

According to ohm's law the potential difference is directly proportional to the current flowing. The formula which is derived from the ohm's law is said to be,

Resistance= $\frac{potential difference in Volt}{Current flowing in ampere}$

• Or , R= 6V/2A = 3 ohm.

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