Question

A small light bulb is connected to a 6v battery and draws 2a of current what is the net resisttance of the bulb

Answer 1

Answer:

The question is good...!

Voltage(V) = 6V

Current(I) = 2A

By Sir Ohm's Law

V = I × R

6 = 2 × R

therefore, R = 6/2 ==> 3 Ω (ohm)

Thus the net resistance is 3 Ω (Ohm)

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Answer 2

Concept:

Problems involving voltage, current and resistance are solved by using Ohm's law which states that voltage or potential difference between two points in a circuit is directly proportional to the product of current drawn and net resistance i.e V= IR

Given:

small light bulb is connected to a 6v battery and draws 2a of current

Find:

We are required to find the net resistance of the bulb

Solution:

By considering the given data and using Ohm's law,

V=IR

v= 6v

i=2a

6= 2 x R

R= 6/2=3 OHM

Hence the resistance is 3 ohm

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